Base | Representation |
---|---|
bin | 10010000011110011011… |
… | …101110101010111000001 |
3 | 11101122022212210120201121 |
4 | 102003303131311113001 |
5 | 130313120011443343 |
6 | 2350042420432241 |
7 | 155443003463353 |
oct | 22036335652701 |
9 | 4348285716647 |
10 | 1241035265473 |
11 | 439358065433 |
12 | 180630248681 |
13 | 9004bca3c93 |
14 | 440d03c30d3 |
15 | 2243751caed |
hex | 120f37755c1 |
1241035265473 has 2 divisors, whose sum is σ = 1241035265474. Its totient is φ = 1241035265472.
The previous prime is 1241035265461. The next prime is 1241035265521. The reversal of 1241035265473 is 3745625301421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1144371481009 + 96663784464 = 1069753^2 + 310908^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1241035265473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1241035265573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620517632736 + 620517632737.
It is an arithmetic number, because the mean of its divisors is an integer number (620517632737).
Almost surely, 21241035265473 is an apocalyptic number.
It is an amenable number.
1241035265473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241035265473 is an equidigital number, since it uses as much as digits as its factorization.
1241035265473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 43.
The spelling of 1241035265473 in words is "one trillion, two hundred forty-one billion, thirty-five million, two hundred sixty-five thousand, four hundred seventy-three".
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