Base | Representation |
---|---|
bin | 1011010010011011101101… |
… | …0100100000101101100011 |
3 | 1121221111202001200021102111 |
4 | 2310212323110200231203 |
5 | 3111321322112000103 |
6 | 42221401325500151 |
7 | 2420454443556463 |
oct | 264467324405543 |
9 | 47844661607374 |
10 | 12411303234403 |
11 | 3a55671128537 |
12 | 1485488411657 |
13 | 6c04c4a165b8 |
14 | 30c9d3027ba3 |
15 | 167ca6d0586d |
hex | b49bb520b63 |
12411303234403 has 2 divisors, whose sum is σ = 12411303234404. Its totient is φ = 12411303234402.
The previous prime is 12411303234397. The next prime is 12411303234427. The reversal of 12411303234403 is 30443230311421.
12411303234403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12411303234403 is a prime.
It is not a weakly prime, because it can be changed into another prime (12411303234443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6205651617201 + 6205651617202.
It is an arithmetic number, because the mean of its divisors is an integer number (6205651617202).
Almost surely, 212411303234403 is an apocalyptic number.
12411303234403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12411303234403 is an equidigital number, since it uses as much as digits as its factorization.
12411303234403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 12411303234403 its reverse (30443230311421), we get a palindrome (42854533545824).
The spelling of 12411303234403 in words is "twelve trillion, four hundred eleven billion, three hundred three million, two hundred thirty-four thousand, four hundred three".
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