Base | Representation |
---|---|
bin | 10010000100001001111… |
… | …000110000011111011011 |
3 | 11101200022002121022201011 |
4 | 102010021320300133123 |
5 | 130314402311002141 |
6 | 2350144015034351 |
7 | 155455221661204 |
oct | 22041170603733 |
9 | 4350262538634 |
10 | 1241411422171 |
11 | 439530425538 |
12 | 18071620b9b7 |
13 | 900abbb79cb |
14 | 4412833c5ab |
15 | 2245a571881 |
hex | 12109e307db |
1241411422171 has 2 divisors, whose sum is σ = 1241411422172. Its totient is φ = 1241411422170.
The previous prime is 1241411422081. The next prime is 1241411422193. The reversal of 1241411422171 is 1712241141421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1241411422171 - 215 = 1241411389403 is a prime.
It is a super-2 number, since 2×12414114221712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1241411422271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620705711085 + 620705711086.
It is an arithmetic number, because the mean of its divisors is an integer number (620705711086).
Almost surely, 21241411422171 is an apocalyptic number.
1241411422171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241411422171 is an equidigital number, since it uses as much as digits as its factorization.
1241411422171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3584, while the sum is 31.
Adding to 1241411422171 its reverse (1712241141421), we get a palindrome (2953652563592).
The spelling of 1241411422171 in words is "one trillion, two hundred forty-one billion, four hundred eleven million, four hundred twenty-two thousand, one hundred seventy-one".
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