Base | Representation |
---|---|
bin | 10111000111111011… |
… | …11100101110000001 |
3 | 1012001012021010112021 |
4 | 23203331330232001 |
5 | 200411114231423 |
6 | 5411520001441 |
7 | 616434243154 |
oct | 134375745601 |
9 | 35035233467 |
10 | 12414602113 |
11 | 52a07a0351 |
12 | 24a5760281 |
13 | 122b019614 |
14 | 85ab03c9b |
15 | 4c9d6a95d |
hex | 2e3f7cb81 |
12414602113 has 2 divisors, whose sum is σ = 12414602114. Its totient is φ = 12414602112.
The previous prime is 12414602099. The next prime is 12414602203. The reversal of 12414602113 is 31120641421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10826818704 + 1587783409 = 104052^2 + 39847^2 .
It is a cyclic number.
It is not a de Polignac number, because 12414602113 - 213 = 12414593921 is a prime.
It is not a weakly prime, because it can be changed into another prime (12414609113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6207301056 + 6207301057.
It is an arithmetic number, because the mean of its divisors is an integer number (6207301057).
Almost surely, 212414602113 is an apocalyptic number.
It is an amenable number.
12414602113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12414602113 is an equidigital number, since it uses as much as digits as its factorization.
12414602113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
The spelling of 12414602113 in words is "twelve billion, four hundred fourteen million, six hundred two thousand, one hundred thirteen".
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