Base | Representation |
---|---|
bin | 10010000100001111011… |
… | …010101110000010101001 |
3 | 11101200112120012111012122 |
4 | 102010033122232002221 |
5 | 130320100034223423 |
6 | 2350201131521025 |
7 | 155460426450665 |
oct | 22041732560251 |
9 | 4350476174178 |
10 | 1241504211113 |
11 | 439578841211 |
12 | 1807412b9175 |
13 | 900c51a51ca |
14 | 441367b38a5 |
15 | 2246379e8c8 |
hex | 1210f6ae0a9 |
1241504211113 has 2 divisors, whose sum is σ = 1241504211114. Its totient is φ = 1241504211112.
The previous prime is 1241504211107. The next prime is 1241504211137. The reversal of 1241504211113 is 3111124051421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1240488067984 + 1016143129 = 1113772^2 + 31877^2 .
It is a cyclic number.
It is not a de Polignac number, because 1241504211113 - 26 = 1241504211049 is a prime.
It is a super-2 number, since 2×12415042111132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1241504211413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620752105556 + 620752105557.
It is an arithmetic number, because the mean of its divisors is an integer number (620752105557).
Almost surely, 21241504211113 is an apocalyptic number.
It is an amenable number.
1241504211113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241504211113 is an equidigital number, since it uses as much as digits as its factorization.
1241504211113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 26.
Adding to 1241504211113 its reverse (3111124051421), we get a palindrome (4352628262534).
The spelling of 1241504211113 in words is "one trillion, two hundred forty-one billion, five hundred four million, two hundred eleven thousand, one hundred thirteen".
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