Base | Representation |
---|---|
bin | 10010000100011110111… |
… | …011101000010001011001 |
3 | 11101201012200222100121011 |
4 | 102010132323220101121 |
5 | 130321113202341343 |
6 | 2350243030413521 |
7 | 155500040031304 |
oct | 22043673502131 |
9 | 4351180870534 |
10 | 1241764496473 |
11 | 4396a175a486 |
12 | 1807b45012a1 |
13 | 901370a9307 |
14 | 4415d1a9b3b |
15 | 2247b56629d |
hex | 1211eee8459 |
1241764496473 has 2 divisors, whose sum is σ = 1241764496474. Its totient is φ = 1241764496472.
The previous prime is 1241764496431. The next prime is 1241764496501. The reversal of 1241764496473 is 3746944671421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 809994600009 + 431769896464 = 899997^2 + 657092^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1241764496473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1241764466473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620882248236 + 620882248237.
It is an arithmetic number, because the mean of its divisors is an integer number (620882248237).
Almost surely, 21241764496473 is an apocalyptic number.
It is an amenable number.
1241764496473 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241764496473 is an equidigital number, since it uses as much as digits as its factorization.
1241764496473 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24385536, while the sum is 58.
The spelling of 1241764496473 in words is "one trillion, two hundred forty-one billion, seven hundred sixty-four million, four hundred ninety-six thousand, four hundred seventy-three".
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