Base | Representation |
---|---|
bin | 10111001000101000… |
… | …01100100011010011 |
3 | 1012001121020102112221 |
4 | 23210110030203103 |
5 | 200414112343011 |
6 | 5412245001511 |
7 | 616534643140 |
oct | 134424144323 |
9 | 35047212487 |
10 | 12420434131 |
11 | 52a4013aa6 |
12 | 24a76b3297 |
13 | 122c2ac011 |
14 | 85b7c13c7 |
15 | 4ca61d971 |
hex | 2e450c8d3 |
12420434131 has 8 divisors (see below), whose sum is σ = 14198812160. Its totient is φ = 10643063688.
The previous prime is 12420434077. The next prime is 12420434137. The reversal of 12420434131 is 13143402421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12420434131 - 211 = 12420432083 is a prime.
It is a super-2 number, since 2×124204341312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12420434096 and 12420434105.
It is not an unprimeable number, because it can be changed into a prime (12420434137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 225291 + ... + 274948.
It is an arithmetic number, because the mean of its divisors is an integer number (1774851520).
Almost surely, 212420434131 is an apocalyptic number.
12420434131 is a deficient number, since it is larger than the sum of its proper divisors (1778378029).
12420434131 is an equidigital number, since it uses as much as digits as its factorization.
12420434131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 503793.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12420434131 its reverse (13143402421), we get a palindrome (25563836552).
The spelling of 12420434131 in words is "twelve billion, four hundred twenty million, four hundred thirty-four thousand, one hundred thirty-one".
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