Base | Representation |
---|---|
bin | 11100001111110011100000… |
… | …101001110111100000011011 |
3 | 121021212101222002022021112202 |
4 | 130033303200221313200123 |
5 | 112240401403201004042 |
6 | 1120115041351200415 |
7 | 35111264660350541 |
oct | 3417634051674033 |
9 | 537771862267482 |
10 | 124231403141147 |
11 | 36647273404795 |
12 | 11b24a6567610b |
13 | 5441c81517aa3 |
14 | 2296b90dc7d91 |
15 | e56825974632 |
hex | 70fce0a7781b |
124231403141147 has 2 divisors, whose sum is σ = 124231403141148. Its totient is φ = 124231403141146.
The previous prime is 124231403140987. The next prime is 124231403141159. The reversal of 124231403141147 is 741141304132421.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124231403141147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 124231403141147.
It is not a weakly prime, because it can be changed into another prime (124231403161147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62115701570573 + 62115701570574.
It is an arithmetic number, because the mean of its divisors is an integer number (62115701570574).
Almost surely, 2124231403141147 is an apocalyptic number.
124231403141147 is a deficient number, since it is larger than the sum of its proper divisors (1).
124231403141147 is an equidigital number, since it uses as much as digits as its factorization.
124231403141147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 38.
Adding to 124231403141147 its reverse (741141304132421), we get a palindrome (865372707273568).
The spelling of 124231403141147 in words is "one hundred twenty-four trillion, two hundred thirty-one billion, four hundred three million, one hundred forty-one thousand, one hundred forty-seven".
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