Base | Representation |
---|---|
bin | 111001111000110110… |
… | …0101100110110101011 |
3 | 102212212122221011210021 |
4 | 1303301230230312223 |
5 | 4014043403031103 |
6 | 133035322501311 |
7 | 11660422340446 |
oct | 1636154546653 |
9 | 385778834707 |
10 | 124314111403 |
11 | 487a3090949 |
12 | 20114664837 |
13 | b951c07901 |
14 | 60342a465d |
15 | 3378ac5bbd |
hex | 1cf1b2cdab |
124314111403 has 4 divisors (see below), whose sum is σ = 124602543648. Its totient is φ = 124025679160.
The previous prime is 124314111359. The next prime is 124314111407. The reversal of 124314111403 is 304111413421.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304111413421 = 300023 ⋅1013627.
It is a cyclic number.
It is not a de Polignac number, because 124314111403 - 217 = 124313980331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (124314111407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144215476 + ... + 144216337.
It is an arithmetic number, because the mean of its divisors is an integer number (31150635912).
Almost surely, 2124314111403 is an apocalyptic number.
124314111403 is a deficient number, since it is larger than the sum of its proper divisors (288432245).
124314111403 is an equidigital number, since it uses as much as digits as its factorization.
124314111403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 288432244.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 124314111403 its reverse (304111413421), we get a palindrome (428425524824).
The spelling of 124314111403 in words is "one hundred twenty-four billion, three hundred fourteen million, one hundred eleven thousand, four hundred three".
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