Base | Representation |
---|---|
bin | 11100010001000110000001… |
… | …101100101000101001111011 |
3 | 121022011212122212002202022202 |
4 | 130101012001230220221323 |
5 | 112243324332103010233 |
6 | 1120223453242340415 |
7 | 35120552413222565 |
oct | 3421060154505173 |
9 | 538155585082282 |
10 | 124320004344443 |
11 | 366808aa489146 |
12 | 11b3a071aba70b |
13 | 544a4315c01bb |
14 | 229b198208335 |
15 | e58cae0e7be8 |
hex | 711181b28a7b |
124320004344443 has 2 divisors, whose sum is σ = 124320004344444. Its totient is φ = 124320004344442.
The previous prime is 124320004344401. The next prime is 124320004344463. The reversal of 124320004344443 is 344443400023421.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124320004344443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 124320004344397 and 124320004344406.
It is not a weakly prime, because it can be changed into another prime (124320004344463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62160002172221 + 62160002172222.
It is an arithmetic number, because the mean of its divisors is an integer number (62160002172222).
Almost surely, 2124320004344443 is an apocalyptic number.
124320004344443 is a deficient number, since it is larger than the sum of its proper divisors (1).
124320004344443 is an equidigital number, since it uses as much as digits as its factorization.
124320004344443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 442368, while the sum is 38.
Adding to 124320004344443 its reverse (344443400023421), we get a palindrome (468763404367864).
The spelling of 124320004344443 in words is "one hundred twenty-four trillion, three hundred twenty billion, four million, three hundred forty-four thousand, four hundred forty-three".
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