Base | Representation |
---|---|
bin | 10010000101110110011… |
… | …111000011100100101011 |
3 | 11101212000001222102222101 |
4 | 102011312133003210223 |
5 | 130332120222314011 |
6 | 2351044502234231 |
7 | 155551324356211 |
oct | 22056637034453 |
9 | 4355001872871 |
10 | 1243233401131 |
11 | 43a285931277 |
12 | 180b44425977 |
13 | 9030c501b77 |
14 | 4425c2d6cb1 |
15 | 225154bc2c1 |
hex | 121767c392b |
1243233401131 has 2 divisors, whose sum is σ = 1243233401132. Its totient is φ = 1243233401130.
The previous prime is 1243233401063. The next prime is 1243233401147. The reversal of 1243233401131 is 1311043323421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1243233401131 - 213 = 1243233392939 is a prime.
It is a super-2 number, since 2×12432334011312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1243233401131.
It is not a weakly prime, because it can be changed into another prime (1243233404131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621616700565 + 621616700566.
It is an arithmetic number, because the mean of its divisors is an integer number (621616700566).
Almost surely, 21243233401131 is an apocalyptic number.
1243233401131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1243233401131 is an equidigital number, since it uses as much as digits as its factorization.
1243233401131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1243233401131 its reverse (1311043323421), we get a palindrome (2554276724552).
The spelling of 1243233401131 in words is "one trillion, two hundred forty-three billion, two hundred thirty-three million, four hundred one thousand, one hundred thirty-one".
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