Base | Representation |
---|---|
bin | 10010000101110110111… |
… | …100111001000100100001 |
3 | 11101212000121200210210020 |
4 | 102011312330321010201 |
5 | 130332124223104213 |
6 | 2351045342024053 |
7 | 155551451012640 |
oct | 22056674710441 |
9 | 4355017623706 |
10 | 1243241222433 |
11 | 43a28a293561 |
12 | 180b46b78029 |
13 | 9031100cb62 |
14 | 4425d371357 |
15 | 22516014923 |
hex | 12176f39121 |
1243241222433 has 16 divisors (see below), whose sum is σ = 1902808473600. Its totient is φ = 707293933776.
The previous prime is 1243241222407. The next prime is 1243241222479. The reversal of 1243241222433 is 3342221423421.
It is a happy number.
It is not a de Polignac number, because 1243241222433 - 222 = 1243237028129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1243241222394 and 1243241222403.
It is not an unprimeable number, because it can be changed into a prime (1243241222633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 130396033 + ... + 130405566.
It is an arithmetic number, because the mean of its divisors is an integer number (118925529600).
Almost surely, 21243241222433 is an apocalyptic number.
It is an amenable number.
1243241222433 is a deficient number, since it is larger than the sum of its proper divisors (659567251167).
1243241222433 is a wasteful number, since it uses less digits than its factorization.
1243241222433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 260801836.
The product of its digits is 55296, while the sum is 33.
Adding to 1243241222433 its reverse (3342221423421), we get a palindrome (4585462645854).
The spelling of 1243241222433 in words is "one trillion, two hundred forty-three billion, two hundred forty-one million, two hundred twenty-two thousand, four hundred thirty-three".
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