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1243321240481 is a prime number
BaseRepresentation
bin10010000101111011101…
…110001000101110100001
311101212020012021010220122
4102011323232020232201
5130332310214143411
62351101321050025
7155553442112465
oct22057356105641
94355205233818
101243321240481
1143a320477281
12180b69926915
1390324778508
1444269c404a5
152251d06d9db
hex1217bb88ba1

1243321240481 has 2 divisors, whose sum is σ = 1243321240482. Its totient is φ = 1243321240480.

The previous prime is 1243321240319. The next prime is 1243321240489. The reversal of 1243321240481 is 1840421233421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1123619080081 + 119702160400 = 1060009^2 + 345980^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1243321240481 is a prime.

It is a super-2 number, since 2×12433212404812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1243321240489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621660620240 + 621660620241.

It is an arithmetic number, because the mean of its divisors is an integer number (621660620241).

Almost surely, 21243321240481 is an apocalyptic number.

It is an amenable number.

1243321240481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243321240481 is an equidigital number, since it uses as much as digits as its factorization.

1243321240481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 35.

The spelling of 1243321240481 in words is "one trillion, two hundred forty-three billion, three hundred twenty-one million, two hundred forty thousand, four hundred eighty-one".