Base | Representation |
---|---|
bin | 10010000110001001011… |
… | …111100011110001100100 |
3 | 11101212211022001012011111 |
4 | 102012021133203301210 |
5 | 130333243342101012 |
6 | 2351140253314404 |
7 | 155562246101002 |
oct | 22061137436144 |
9 | 4355738035144 |
10 | 1243552300132 |
11 | 43a42994386a |
12 | 181013195a04 |
13 | 903605b8bbc |
14 | 4428c7c9a72 |
15 | 225334b0ba7 |
hex | 121897e3c64 |
1243552300132 has 6 divisors (see below), whose sum is σ = 2176216525238. Its totient is φ = 621776150064.
The previous prime is 1243552300099. The next prime is 1243552300223. The reversal of 1243552300132 is 2310032553421.
It can be written as a sum of positive squares in only one way, i.e., 1189308026916 + 54244273216 = 1090554^2 + 232904^2 .
It is a super-3 number, since 3×12435523001323 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1243552300094 and 1243552300103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155444037513 + ... + 155444037520.
Almost surely, 21243552300132 is an apocalyptic number.
It is an amenable number.
1243552300132 is a deficient number, since it is larger than the sum of its proper divisors (932664225106).
1243552300132 is a wasteful number, since it uses less digits than its factorization.
1243552300132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 310888075037 (or 310888075035 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 1243552300132 its reverse (2310032553421), we get a palindrome (3553584853553).
The spelling of 1243552300132 in words is "one trillion, two hundred forty-three billion, five hundred fifty-two million, three hundred thousand, one hundred thirty-two".
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