Base | Representation |
---|---|
bin | 10111001010110001… |
… | …01010111100110001 |
3 | 1012002212000101201221 |
4 | 23211120222330301 |
5 | 200433211300213 |
6 | 5414125425041 |
7 | 620143344316 |
oct | 134530527461 |
9 | 35085011657 |
10 | 12438384433 |
11 | 5303164362 |
12 | 24b170b181 |
13 | 1232c254b7 |
14 | 85dd34d0d |
15 | 4cbeb738d |
hex | 2e562af31 |
12438384433 has 2 divisors, whose sum is σ = 12438384434. Its totient is φ = 12438384432.
The previous prime is 12438384397. The next prime is 12438384467. The reversal of 12438384433 is 33448383421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11425044544 + 1013339889 = 106888^2 + 31833^2 .
It is an emirp because it is prime and its reverse (33448383421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12438384433 - 225 = 12404830001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12438384433.
It is not a weakly prime, because it can be changed into another prime (12438384733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6219192216 + 6219192217.
It is an arithmetic number, because the mean of its divisors is an integer number (6219192217).
Almost surely, 212438384433 is an apocalyptic number.
It is an amenable number.
12438384433 is a deficient number, since it is larger than the sum of its proper divisors (1).
12438384433 is an equidigital number, since it uses as much as digits as its factorization.
12438384433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 663552, while the sum is 43.
The spelling of 12438384433 in words is "twelve billion, four hundred thirty-eight million, three hundred eighty-four thousand, four hundred thirty-three".
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