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124401044113 is a prime number
BaseRepresentation
bin111001111011011100…
…0010100101010010001
3102220002201111211001021
41303312320110222101
54014233131402423
6133052110035441
711662526266543
oct1636670245221
9386081454037
10124401044113
1148838167765
12201397a8b81
13b966c24698
146041a53693
15338154895d
hex1cf6e14a91

124401044113 has 2 divisors, whose sum is σ = 124401044114. Its totient is φ = 124401044112.

The previous prime is 124401044099. The next prime is 124401044123. The reversal of 124401044113 is 311440104421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98424630529 + 25976413584 = 313727^2 + 161172^2 .

It is an emirp because it is prime and its reverse (311440104421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 124401044113 - 221 = 124398946961 is a prime.

It is not a weakly prime, because it can be changed into another prime (124401044123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62200522056 + 62200522057.

It is an arithmetic number, because the mean of its divisors is an integer number (62200522057).

Almost surely, 2124401044113 is an apocalyptic number.

It is an amenable number.

124401044113 is a deficient number, since it is larger than the sum of its proper divisors (1).

124401044113 is an equidigital number, since it uses as much as digits as its factorization.

124401044113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 124401044113 its reverse (311440104421), we get a palindrome (435841148534).

The spelling of 124401044113 in words is "one hundred twenty-four billion, four hundred one million, forty-four thousand, one hundred thirteen".