Base | Representation |
---|---|
bin | 10010000110100101100… |
… | …000100011011111011001 |
3 | 11101221001001110211112211 |
4 | 102012211200203133121 |
5 | 130340224203320121 |
6 | 2351255043435121 |
7 | 155610014163352 |
oct | 22064540433731 |
9 | 4357031424484 |
10 | 1244022323161 |
11 | 43a650196052 |
12 | 181124685aa1 |
13 | 90406aa6637 |
14 | 442d4dbad29 |
15 | 2255e8a6ce1 |
hex | 121a58237d9 |
1244022323161 has 2 divisors, whose sum is σ = 1244022323162. Its totient is φ = 1244022323160.
The previous prime is 1244022323083. The next prime is 1244022323171. The reversal of 1244022323161 is 1613232204421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1143616360000 + 100405963161 = 1069400^2 + 316869^2 .
It is a cyclic number.
It is not a de Polignac number, because 1244022323161 - 227 = 1243888105433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1244022323171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622011161580 + 622011161581.
It is an arithmetic number, because the mean of its divisors is an integer number (622011161581).
Almost surely, 21244022323161 is an apocalyptic number.
It is an amenable number.
1244022323161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1244022323161 is an equidigital number, since it uses as much as digits as its factorization.
1244022323161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1244022323161 its reverse (1613232204421), we get a palindrome (2857254527582).
The spelling of 1244022323161 in words is "one trillion, two hundred forty-four billion, twenty-two million, three hundred twenty-three thousand, one hundred sixty-one".
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