Base | Representation |
---|---|
bin | 10010000110101100001… |
… | …100000111000000100011 |
3 | 11101221022212101010201212 |
4 | 102012230030013000203 |
5 | 130340441401413011 |
6 | 2351314130020335 |
7 | 155612544643133 |
oct | 22065414070043 |
9 | 4357285333655 |
10 | 1244134404131 |
11 | 43a6a8489153 |
12 | 1811561176ab |
13 | 90424089c38 |
14 | 44305c34ac3 |
15 | 2256964608b |
hex | 121ac307023 |
1244134404131 has 2 divisors, whose sum is σ = 1244134404132. Its totient is φ = 1244134404130.
The previous prime is 1244134404103. The next prime is 1244134404169. The reversal of 1244134404131 is 1314044314421.
It is a weak prime.
It is an emirp because it is prime and its reverse (1314044314421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1244134404131 - 214 = 1244134387747 is a prime.
It is a super-2 number, since 2×12441344041312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1244134404101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622067202065 + 622067202066.
It is an arithmetic number, because the mean of its divisors is an integer number (622067202066).
Almost surely, 21244134404131 is an apocalyptic number.
1244134404131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1244134404131 is an equidigital number, since it uses as much as digits as its factorization.
1244134404131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 1244134404131 its reverse (1314044314421), we get a palindrome (2558178718552).
The spelling of 1244134404131 in words is "one trillion, two hundred forty-four billion, one hundred thirty-four million, four hundred four thousand, one hundred thirty-one".
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