Base | Representation |
---|---|
bin | 1011010100001111010111… |
… | …1011100100100100011111 |
3 | 1122001110212212010121122110 |
4 | 2311003311323210210133 |
5 | 3112323413414322143 |
6 | 42243534242045103 |
7 | 2422634031144450 |
oct | 265036573444437 |
9 | 48043785117573 |
10 | 12442351323423 |
11 | 3a67853a5033a |
12 | 148b4b2349793 |
13 | 6c34022851c8 |
14 | 3102da73b127 |
15 | 1689c295e533 |
hex | b50f5ee491f |
12442351323423 has 32 divisors (see below), whose sum is σ = 19001627389440. Its totient is φ = 7094233405440.
The previous prime is 12442351323421. The next prime is 12442351323499. The reversal of 12442351323423 is 32432315324421.
It is not a de Polignac number, because 12442351323423 - 21 = 12442351323421 is a prime.
It is a super-3 number, since 3×124423513234233 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12442351323421) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 21777283 + ... + 22341323.
It is an arithmetic number, because the mean of its divisors is an integer number (593800855920).
Almost surely, 212442351323423 is an apocalyptic number.
12442351323423 is a deficient number, since it is larger than the sum of its proper divisors (6559276066017).
12442351323423 is a wasteful number, since it uses less digits than its factorization.
12442351323423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 566367.
The product of its digits is 414720, while the sum is 39.
Adding to 12442351323423 its reverse (32432315324421), we get a palindrome (44874666647844).
The spelling of 12442351323423 in words is "twelve trillion, four hundred forty-two billion, three hundred fifty-one million, three hundred twenty-three thousand, four hundred twenty-three".
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