1244311400041 has 2 divisors, whose sum is σ = 1244311400042. Its totient is φ = 1244311400040.

The previous prime is 1244311399999. The next prime is 1244311400089. The reversal of 1244311400041 is 1400041134421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1244251011600 + 60388441 = 1115460^2 + 7771^2 .

It is a cyclic number.

It is not a de Polignac number, because 1244311400041 - 2¹¹ = 1244311397993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1244311399979 and 1244311400015.

It is not a weakly prime, because it can be changed into another prime (1244311430041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622155700020 + 622155700021.

It is an arithmetic number, because the mean of its divisors is an integer number (622155700021).

Almost surely, 2^{1244311400041} is an apocalyptic number.

It is an amenable number.

1244311400041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1244311400041 is an equidigital number, since it uses as much as digits as its factorization.

1244311400041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1244311400041 its reverse (1400041134421), we get a palindrome (2644352534462).

The spelling of 1244311400041 in words is "one trillion, two hundred forty-four billion, three hundred eleven million, four hundred thousand, forty-one".