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12444243203993 is a prime number
BaseRepresentation
bin1011010100010110011010…
…1100100001011110011001
31122001122202201001002220012
42311011212230201132121
53112341302230011433
642244450103411305
72423031642646316
oct265054654413631
948048681032805
1012444243203993
113a686349601a7
12148b93ba53b35
136c3644205173
14310439acdd0d
15168a83ab6848
hexb5166b21799

12444243203993 has 2 divisors, whose sum is σ = 12444243203994. Its totient is φ = 12444243203992.

The previous prime is 12444243203971. The next prime is 12444243204139. The reversal of 12444243203993 is 39930234244421.

12444243203993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11102843760649 + 1341399443344 = 3332093^2 + 1158188^2 .

It is a cyclic number.

It is not a de Polignac number, because 12444243203993 - 236 = 12375523727257 is a prime.

It is a super-2 number, since 2×124442432039932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12444243203923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6222121601996 + 6222121601997.

It is an arithmetic number, because the mean of its divisors is an integer number (6222121601997).

Almost surely, 212444243203993 is an apocalyptic number.

It is an amenable number.

12444243203993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12444243203993 is an equidigital number, since it uses as much as digits as its factorization.

12444243203993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4478976, while the sum is 50.

The spelling of 12444243203993 in words is "twelve trillion, four hundred forty-four billion, two hundred forty-three million, two hundred three thousand, nine hundred ninety-three".