Base | Representation |
---|---|
bin | 1011010100101100010010… |
… | …0001011101100110101001 |
3 | 1122002012220201211121102011 |
4 | 2311023010201131212221 |
5 | 3112440312224031103 |
6 | 42251300323235521 |
7 | 2423330250464311 |
oct | 265130441354651 |
9 | 48065821747364 |
10 | 12450112330153 |
11 | 3a70076922593 |
12 | 1490ab9518ba1 |
13 | 6c406b13a794 |
14 | 310835392441 |
15 | 168cc8e9bd6d |
hex | b52c485d9a9 |
12450112330153 has 2 divisors, whose sum is σ = 12450112330154. Its totient is φ = 12450112330152.
The previous prime is 12450112330049. The next prime is 12450112330241. The reversal of 12450112330153 is 35103321105421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11044967619609 + 1405144710544 = 3323397^2 + 1185388^2 .
It is an emirp because it is prime and its reverse (35103321105421) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12450112330153 is a prime.
It is not a weakly prime, because it can be changed into another prime (12450112337153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6225056165076 + 6225056165077.
It is an arithmetic number, because the mean of its divisors is an integer number (6225056165077).
Almost surely, 212450112330153 is an apocalyptic number.
It is an amenable number.
12450112330153 is a deficient number, since it is larger than the sum of its proper divisors (1).
12450112330153 is an equidigital number, since it uses as much as digits as its factorization.
12450112330153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 12450112330153 its reverse (35103321105421), we get a palindrome (47553433435574).
The spelling of 12450112330153 in words is "twelve trillion, four hundred fifty billion, one hundred twelve million, three hundred thirty thousand, one hundred fifty-three".
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