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12454430425113 = 34151476808371
BaseRepresentation
bin1011010100111100010111…
…1001101100000000011001
31122002122001200002120010010
42311033011321230000121
53113023133142100423
642253253015112133
72423542252623405
oct265170571540031
948078050076103
1012454430425113
113a7199231a206
121491903672649
136c45a8924261
14310b24a6a105
15168e7d107693
hexb53c5e6c019

12454430425113 has 4 divisors (see below), whose sum is σ = 16605907233488. Its totient is φ = 8302953616740.

The previous prime is 12454430425111. The next prime is 12454430425117. The reversal of 12454430425113 is 31152403445421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12454430425113 - 21 = 12454430425111 is a prime.

It is a super-2 number, since 2×124544304251132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12454430425111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2075738404183 + ... + 2075738404188.

It is an arithmetic number, because the mean of its divisors is an integer number (4151476808372).

Almost surely, 212454430425113 is an apocalyptic number.

It is an amenable number.

12454430425113 is a deficient number, since it is larger than the sum of its proper divisors (4151476808375).

12454430425113 is an equidigital number, since it uses as much as digits as its factorization.

12454430425113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4151476808374.

The product of its (nonzero) digits is 230400, while the sum is 39.

The spelling of 12454430425113 in words is "twelve trillion, four hundred fifty-four billion, four hundred thirty million, four hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 3 4151476808371 12454430425113