Base | Representation |
---|---|
bin | 10111001101011001… |
… | …10001111011111011 |
3 | 1012011101111120212222 |
4 | 23212230301323323 |
5 | 201004332330042 |
6 | 5420234154255 |
7 | 620531635301 |
oct | 134654617373 |
9 | 35141446788 |
10 | 12460433147 |
11 | 5314653938 |
12 | 24b8b8298b |
13 | 1237675286 |
14 | 862c34271 |
15 | 4cddc02d2 |
hex | 2e6b31efb |
12460433147 has 2 divisors, whose sum is σ = 12460433148. Its totient is φ = 12460433146.
The previous prime is 12460433143. The next prime is 12460433201. The reversal of 12460433147 is 74133406421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12460433147 - 22 = 12460433143 is a prime.
It is not a weakly prime, because it can be changed into another prime (12460433143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6230216573 + 6230216574.
It is an arithmetic number, because the mean of its divisors is an integer number (6230216574).
Almost surely, 212460433147 is an apocalyptic number.
12460433147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12460433147 is an equidigital number, since it uses as much as digits as its factorization.
12460433147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 12460433147 its reverse (74133406421), we get a palindrome (86593839568).
It can be divided in two parts, 124604 and 33147, that added together give a palindrome (157751).
The spelling of 12460433147 in words is "twelve billion, four hundred sixty million, four hundred thirty-three thousand, one hundred forty-seven".
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