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12471235365097 is a prime number
BaseRepresentation
bin1011010101111010111110…
…0011011100100011101001
31122011020102211112221222201
42311132233203130203221
53113312042223140342
642305112331220201
72425005560353465
oct265365743344351
948136384487881
1012471235365097
113a7902626a363
1214950135a7661
136c605639ca22
1431187a8914a5
151696135eddb7
hexb57af8dc8e9

12471235365097 has 2 divisors, whose sum is σ = 12471235365098. Its totient is φ = 12471235365096.

The previous prime is 12471235365077. The next prime is 12471235365109. The reversal of 12471235365097 is 79056353217421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12469825437696 + 1409927401 = 3531264^2 + 37549^2 .

It is an emirp because it is prime and its reverse (79056353217421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12471235365097 - 211 = 12471235363049 is a prime.

It is a super-4 number, since 4×124712353650974 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12471235365037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6235617682548 + 6235617682549.

It is an arithmetic number, because the mean of its divisors is an integer number (6235617682549).

Almost surely, 212471235365097 is an apocalyptic number.

It is an amenable number.

12471235365097 is a deficient number, since it is larger than the sum of its proper divisors (1).

12471235365097 is an equidigital number, since it uses as much as digits as its factorization.

12471235365097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9525600, while the sum is 55.

The spelling of 12471235365097 in words is "twelve trillion, four hundred seventy-one billion, two hundred thirty-five million, three hundred sixty-five thousand, ninety-seven".