Base | Representation |
---|---|
bin | 10111001111111000… |
… | …11011010000010001 |
3 | 1012012211210022221222 |
4 | 23213330123100101 |
5 | 201030203434021 |
6 | 5422301454425 |
7 | 621204254012 |
oct | 134774332021 |
9 | 35184708858 |
10 | 12481311761 |
11 | 5325414296 |
12 | 2503b71415 |
13 | 123baa5599 |
14 | 86590b009 |
15 | 4d0b466ab |
hex | 2e7f1b411 |
12481311761 has 2 divisors, whose sum is σ = 12481311762. Its totient is φ = 12481311760.
The previous prime is 12481311743. The next prime is 12481311811. The reversal of 12481311761 is 16711318421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10860766225 + 1620545536 = 104215^2 + 40256^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12481311761 is a prime.
It is a super-2 number, since 2×124813117612 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12481314761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6240655880 + 6240655881.
It is an arithmetic number, because the mean of its divisors is an integer number (6240655881).
Almost surely, 212481311761 is an apocalyptic number.
It is an amenable number.
12481311761 is a deficient number, since it is larger than the sum of its proper divisors (1).
12481311761 is an equidigital number, since it uses as much as digits as its factorization.
12481311761 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8064, while the sum is 35.
The spelling of 12481311761 in words is "twelve billion, four hundred eighty-one million, three hundred eleven thousand, seven hundred sixty-one".
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