Base | Representation |
---|---|
bin | 10111010010001000… |
… | …10011000011010011 |
3 | 1012021011020112122021 |
4 | 23221010103003103 |
5 | 201100014340111 |
6 | 5424213352311 |
7 | 621523354246 |
oct | 135104230323 |
9 | 35234215567 |
10 | 12500152531 |
11 | 5335012679 |
12 | 250a338697 |
13 | 1242971179 |
14 | 86821325d |
15 | 4d2618d71 |
hex | 2e91130d3 |
12500152531 has 2 divisors, whose sum is σ = 12500152532. Its totient is φ = 12500152530.
The previous prime is 12500152523. The next prime is 12500152559. The reversal of 12500152531 is 13525100521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12500152531 - 23 = 12500152523 is a prime.
It is a super-2 number, since 2×125001525312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12500152496 and 12500152505.
It is not a weakly prime, because it can be changed into another prime (12500152031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250076265 + 6250076266.
It is an arithmetic number, because the mean of its divisors is an integer number (6250076266).
Almost surely, 212500152531 is an apocalyptic number.
12500152531 is a deficient number, since it is larger than the sum of its proper divisors (1).
12500152531 is an equidigital number, since it uses as much as digits as its factorization.
12500152531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1500, while the sum is 25.
The spelling of 12500152531 in words is "twelve billion, five hundred million, one hundred fifty-two thousand, five hundred thirty-one".
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