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125011132243 = 151827888293
BaseRepresentation
bin111010001101100111…
…1100111111101010011
3102221200020111111121221
41310123033213331103
54022010322212433
6133232422225511
712013615043254
oct1643317477523
9387606444557
10125011132243
1149020585a28
1220289b85297
13ba33442c8a
14609caa4b2b
1533b9daa72d
hex1d1b3e7f53

125011132243 has 4 divisors (see below), whose sum is σ = 125839020688. Its totient is φ = 124183243800.

The previous prime is 125011132241. The next prime is 125011132291. The reversal of 125011132243 is 342231110521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125011132243 - 21 = 125011132241 is a prime.

It is a super-2 number, since 2×1250111322432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125011132241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 413943996 + ... + 413944297.

It is an arithmetic number, because the mean of its divisors is an integer number (31459755172).

Almost surely, 2125011132243 is an apocalyptic number.

125011132243 is a deficient number, since it is larger than the sum of its proper divisors (827888445).

125011132243 is an equidigital number, since it uses as much as digits as its factorization.

125011132243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 827888444.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 125011132243 its reverse (342231110521), we get a palindrome (467242242764).

The spelling of 125011132243 in words is "one hundred twenty-five billion, eleven million, one hundred thirty-two thousand, two hundred forty-three".

Divisors: 1 151 827888293 125011132243