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12501403143577 is a prime number
BaseRepresentation
bin1011010111101011010110…
…1100011000110110011001
31122021010022021112220011121
42311322311230120312121
53114310333201043302
642331022035325241
72430124265266435
oct265726554306631
948233267486147
1012501403143577
113a8a8a7188897
12149aa32750821
136c8b53449c1a
143130dd2d19c5
1516a2cbd19e37
hexb5eb5b18d99

12501403143577 has 2 divisors, whose sum is σ = 12501403143578. Its totient is φ = 12501403143576.

The previous prime is 12501403143521. The next prime is 12501403143617. The reversal of 12501403143577 is 77534130410521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10622280345856 + 1879122797721 = 3259184^2 + 1370811^2 .

It is an emirp because it is prime and its reverse (77534130410521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12501403143577 is a prime.

It is not a weakly prime, because it can be changed into another prime (12501403143077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250701571788 + 6250701571789.

It is an arithmetic number, because the mean of its divisors is an integer number (6250701571789).

Almost surely, 212501403143577 is an apocalyptic number.

It is an amenable number.

12501403143577 is a deficient number, since it is larger than the sum of its proper divisors (1).

12501403143577 is an equidigital number, since it uses as much as digits as its factorization.

12501403143577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 352800, while the sum is 43.

The spelling of 12501403143577 in words is "twelve trillion, five hundred one billion, four hundred three million, one hundred forty-three thousand, five hundred seventy-seven".