Base | Representation |
---|---|
bin | 111010001101101101… |
… | …1000100111000111011 |
3 | 102221200110011000201101 |
4 | 1310123123010320323 |
5 | 4022012104244311 |
6 | 133233010432231 |
7 | 12013652415562 |
oct | 1643333047073 |
9 | 387613130641 |
10 | 125014134331 |
11 | 49022246499 |
12 | 2028ab92677 |
13 | ba33c54568 |
14 | 609d246bd9 |
15 | 33ba29eec1 |
hex | 1d1b6c4e3b |
125014134331 has 2 divisors, whose sum is σ = 125014134332. Its totient is φ = 125014134330.
The previous prime is 125014134211. The next prime is 125014134337. The reversal of 125014134331 is 133431410521.
It is a strong prime.
It is an emirp because it is prime and its reverse (133431410521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125014134331 - 29 = 125014133819 is a prime.
It is a super-2 number, since 2×1250141343312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 125014134331.
It is not a weakly prime, because it can be changed into another prime (125014134337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62507067165 + 62507067166.
It is an arithmetic number, because the mean of its divisors is an integer number (62507067166).
Almost surely, 2125014134331 is an apocalyptic number.
125014134331 is a deficient number, since it is larger than the sum of its proper divisors (1).
125014134331 is an equidigital number, since it uses as much as digits as its factorization.
125014134331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 125014134331 its reverse (133431410521), we get a palindrome (258445544852).
The spelling of 125014134331 in words is "one hundred twenty-five billion, fourteen million, one hundred thirty-four thousand, three hundred thirty-one".
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