125020121112499 has 2 divisors, whose sum is σ = 125020121112500. Its totient is φ = 125020121112498.

The previous prime is 125020121112463. The next prime is 125020121112511. The reversal of 125020121112499 is 994211121020521.

It is a strong prime.

It is an emirp because it is prime and its reverse (994211121020521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125020121112499 - 2³¹ = 125017973628851 is a prime.

It is a super-3 number, since 3×125020121112499³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (125020121110499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62510060556249 + 62510060556250.

It is an arithmetic number, because the mean of its divisors is an integer number (62510060556250).

Almost surely, 2^{125020121112499} is an apocalyptic number.

125020121112499 is a deficient number, since it is larger than the sum of its proper divisors (1).

125020121112499 is an equidigital number, since it uses as much as digits as its factorization.

125020121112499 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 40.

The spelling of 125020121112499 in words is "one hundred twenty-five trillion, twenty billion, one hundred twenty-one million, one hundred twelve thousand, four hundred ninety-nine".