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12503111147 = 71317555521
BaseRepresentation
bin10111010010011111…
…00101010111101011
31012021100210212002122
423221033211113223
5201101244024042
65424401021455
7621560456042
oct135117452753
935240725078
1012503111147
11533675350a
12250b32488b
131243468a27
14868783559
154d2a007d2
hex2e93e55eb

12503111147 has 8 divisors (see below), whose sum is σ = 12719231712. Its totient is φ = 12288102400.

The previous prime is 12503111111. The next prime is 12503111183. The reversal of 12503111147 is 74111130521.

It is an interprime number because it is at equal distance from previous prime (12503111111) and next prime (12503111183).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12503111147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12503111107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 255254 + ... + 300267.

It is an arithmetic number, because the mean of its divisors is an integer number (1589903964).

Almost surely, 212503111147 is an apocalyptic number.

12503111147 is a deficient number, since it is larger than the sum of its proper divisors (216120565).

12503111147 is an equidigital number, since it uses as much as digits as its factorization.

12503111147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 555909.

The product of its (nonzero) digits is 840, while the sum is 26.

Adding to 12503111147 its reverse (74111130521), we get a palindrome (86614241668).

The spelling of 12503111147 in words is "twelve billion, five hundred three million, one hundred eleven thousand, one hundred forty-seven".

Divisors: 1 71 317 22507 555521 39441991 176100157 12503111147