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12503113 = 71786159
BaseRepresentation
bin101111101100…
…100001001001
3212112020001021
4233230201021
511200044423
61123552441
7211163140
oct57544111
925466037
1012503113
11706a857
12422b721
132789cbc
141936757
15116e95d
hexbec849

12503113 has 4 divisors (see below), whose sum is σ = 14289280. Its totient is φ = 10716948.

The previous prime is 12503059. The next prime is 12503131. The reversal of 12503113 is 31130521.

12503113 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12503113 - 213 = 12494921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12503213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893073 + ... + 893086.

It is an arithmetic number, because the mean of its divisors is an integer number (3572320).

Almost surely, 212503113 is an apocalyptic number.

It is an amenable number.

12503113 is a deficient number, since it is larger than the sum of its proper divisors (1786167).

12503113 is an equidigital number, since it uses as much as digits as its factorization.

12503113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1786166.

The product of its (nonzero) digits is 90, while the sum is 16.

The square root of 12503113 is about 3535.9741232085. The cubic root of 12503113 is about 232.0987057696.

Adding to 12503113 its reverse (31130521), we get a palindrome (43633634).

The spelling of 12503113 in words is "twelve million, five hundred three thousand, one hundred thirteen".

Divisors: 1 7 1786159 12503113