Base | Representation |
---|---|
bin | 10010001100011100100… |
… | …010101010000010000001 |
3 | 11102112021112222220122002 |
4 | 102030130202222002001 |
5 | 130441120432031431 |
6 | 2354215251153345 |
7 | 156221645311334 |
oct | 22143442520201 |
9 | 4375245886562 |
10 | 1250314330241 |
11 | 4422899310a9 |
12 | 18239b8a5855 |
13 | 90b9a502052 |
14 | 447308bc61b |
15 | 227cbe703cb |
hex | 1231c8aa081 |
1250314330241 has 2 divisors, whose sum is σ = 1250314330242. Its totient is φ = 1250314330240.
The previous prime is 1250314330211. The next prime is 1250314330247. The reversal of 1250314330241 is 1420334130521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1111978686016 + 138335644225 = 1054504^2 + 371935^2 .
It is a cyclic number.
It is not a de Polignac number, because 1250314330241 - 218 = 1250314068097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1250314330247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625157165120 + 625157165121.
It is an arithmetic number, because the mean of its divisors is an integer number (625157165121).
Almost surely, 21250314330241 is an apocalyptic number.
It is an amenable number.
1250314330241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1250314330241 is an equidigital number, since it uses as much as digits as its factorization.
1250314330241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 1250314330241 its reverse (1420334130521), we get a palindrome (2670648460762).
The spelling of 1250314330241 in words is "one trillion, two hundred fifty billion, three hundred fourteen million, three hundred thirty thousand, two hundred forty-one".
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