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1250320040257 is a prime number
BaseRepresentation
bin10010001100011100111…
…000011100000101000001
311102112021221202000022011
4102030130320130011001
5130441123412242012
62354220013412521
7156222044662531
oct22143470340501
94375257660264
101250320040257
11442292081122
121823a179a141
1390b9b751062
14447315674c1
15227cc6ec1a7
hex1231ce1c141

1250320040257 has 2 divisors, whose sum is σ = 1250320040258. Its totient is φ = 1250320040256.

The previous prime is 1250320040201. The next prime is 1250320040267. The reversal of 1250320040257 is 7520400230521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1112854096561 + 137465943696 = 1054919^2 + 370764^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1250320040257 is a prime.

It is a super-2 number, since 2×12503200402572 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1250320040267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625160020128 + 625160020129.

It is an arithmetic number, because the mean of its divisors is an integer number (625160020129).

Almost surely, 21250320040257 is an apocalyptic number.

It is an amenable number.

1250320040257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250320040257 is an equidigital number, since it uses as much as digits as its factorization.

1250320040257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 31.

Adding to 1250320040257 its reverse (7520400230521), we get a palindrome (8770720270778).

The spelling of 1250320040257 in words is "one trillion, two hundred fifty billion, three hundred twenty million, forty thousand, two hundred fifty-seven".