Search a number
-
+
12503233001 = 71786176143
BaseRepresentation
bin10111010010100000…
…00011000111101001
31012021101001001020202
423221100003013221
5201101311424001
65424403401545
7621561504230
oct135120030751
935241031222
1012503233001
115336827016
12250b3832b5
1312434ac32c
148687b5b17
154d2a2696b
hex2e94031e9

12503233001 has 4 divisors (see below), whose sum is σ = 14289409152. Its totient is φ = 10717056852.

The previous prime is 12503232991. The next prime is 12503233019. The reversal of 12503233001 is 10033230521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12503233001 - 210 = 12503231977 is a prime.

It is a super-4 number, since 4×125032330014 (a number of 41 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12503233031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893088065 + ... + 893088078.

It is an arithmetic number, because the mean of its divisors is an integer number (3572352288).

Almost surely, 212503233001 is an apocalyptic number.

It is an amenable number.

12503233001 is a deficient number, since it is larger than the sum of its proper divisors (1786176151).

12503233001 is an equidigital number, since it uses as much as digits as its factorization.

12503233001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1786176150.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 12503233001 its reverse (10033230521), we get a palindrome (22536463522).

The spelling of 12503233001 in words is "twelve billion, five hundred three million, two hundred thirty-three thousand, one".

Divisors: 1 7 1786176143 12503233001