Base | Representation |
---|---|
bin | 10010001100011110101… |
… | …010101110111101111001 |
3 | 11102112101001010020010212 |
4 | 102030132222232331321 |
5 | 130441204100031131 |
6 | 2354223003520505 |
7 | 156222560441630 |
oct | 22143652567571 |
9 | 4375331106125 |
10 | 1250350002041 |
11 | 4422a7a85928 |
12 | 1823ab829135 |
13 | 90ba4a1181a |
14 | 44735526517 |
15 | 227d0169a2b |
hex | 1231eaaef79 |
1250350002041 has 32 divisors (see below), whose sum is σ = 1504079635968. Its totient is φ = 1016244472320.
The previous prime is 1250350002001. The next prime is 1250350002049. The reversal of 1250350002041 is 1402000530521.
It is not a de Polignac number, because 1250350002041 - 214 = 1250349985657 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a junction number, because it is equal to n+sod(n) for n = 1250350001998 and 1250350002016.
It is not an unprimeable number, because it can be changed into a prime (1250350002049) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9170021 + ... + 9305373.
It is an arithmetic number, because the mean of its divisors is an integer number (47002488624).
Almost surely, 21250350002041 is an apocalyptic number.
It is an amenable number.
1250350002041 is a deficient number, since it is larger than the sum of its proper divisors (253729633927).
1250350002041 is a wasteful number, since it uses less digits than its factorization.
1250350002041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135881.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 1250350002041 its reverse (1402000530521), we get a palindrome (2652350532562).
The spelling of 1250350002041 in words is "one trillion, two hundred fifty billion, three hundred fifty million, two thousand, forty-one".
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