Base | Representation |
---|---|
bin | 10111010010100100… |
… | …11000010010101011 |
3 | 1012021102012002101202 |
4 | 23221102120102223 |
5 | 201101441002021 |
6 | 5424424434415 |
7 | 621566630501 |
oct | 135122302253 |
9 | 35242162352 |
10 | 12503844011 |
11 | 533710408a |
12 | 250b618a0b |
13 | 1243664489 |
14 | 8688d4671 |
15 | 4d2ae7a0b |
hex | 2e94984ab |
12503844011 has 2 divisors, whose sum is σ = 12503844012. Its totient is φ = 12503844010.
The previous prime is 12503843977. The next prime is 12503844037. The reversal of 12503844011 is 11044830521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12503844011 - 210 = 12503842987 is a prime.
It is a super-2 number, since 2×125038440112 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12503844061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6251922005 + 6251922006.
It is an arithmetic number, because the mean of its divisors is an integer number (6251922006).
Almost surely, 212503844011 is an apocalyptic number.
12503844011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12503844011 is an equidigital number, since it uses as much as digits as its factorization.
12503844011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 29.
The spelling of 12503844011 in words is "twelve billion, five hundred three million, eight hundred forty-four thousand, eleven".
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