12504440121 has 8 divisors (see below), whose sum is σ = 16700992224. Its totient is φ = 8322090720.

The previous prime is 12504440089. The next prime is 12504440131. The reversal of 12504440121 is 12104440521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12504440121 - 2⁵ = 12504440089 is a prime.

It is a super-2 number, since 2×12504440121² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12504440091 and 12504440100.

It is not an unprimeable number, because it can be changed into a prime (12504440131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3548620 + ... + 3552141.

It is an arithmetic number, because the mean of its divisors is an integer number (2087624028).

Almost surely, 2^12504440121 is an apocalyptic number.

It is an amenable number.

12504440121 is a deficient number, since it is larger than the sum of its proper divisors (4196552103).

12504440121 is an equidigital number, since it uses as much as digits as its factorization.

12504440121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7101351.

The product of its (nonzero) digits is 1280, while the sum is 24.

Adding to 12504440121 its reverse (12104440521), we get a palindrome (24608880642).

The spelling of 12504440121 in words is "twelve billion, five hundred four million, four hundred forty thousand, one hundred twenty-one".