125100403 has 4 divisors (see below), whose sum is σ = 129414240. Its totient is φ = 120786568.

The previous prime is 125100397. The next prime is 125100413. The reversal of 125100403 is 304001521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304001521 = 191 ⋅1591631.

It is a cyclic number.

It is not a de Polignac number, because 125100403 - 2¹³ = 125092211 is a prime.

It is a super-2 number, since 2×125100403² = 31300221661524818, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (125100413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2156875 + ... + 2156932.

It is an arithmetic number, because the mean of its divisors is an integer number (32353560).

Almost surely, 2^125100403 is an apocalyptic number.

125100403 is a deficient number, since it is larger than the sum of its proper divisors (4313837).

125100403 is an equidigital number, since it uses as much as digits as its factorization.

125100403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4313836.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 125100403 is about 11184.8291448730. The cubic root of 125100403 is about 500.1338348399.

Adding to 125100403 its reverse (304001521), we get a palindrome (429101924).

The spelling of 125100403 in words is "one hundred twenty-five million, one hundred thousand, four hundred three".