Base | Representation |
---|---|
bin | 10010001101000111010… |
… | …100110110011101010011 |
3 | 11102121010120122222201121 |
4 | 102031013110312131103 |
5 | 130444103211201121 |
6 | 2354414412143111 |
7 | 156245512443166 |
oct | 22150724663523 |
9 | 4377116588647 |
10 | 1251032131411 |
11 | 442618029807 |
12 | 182560167a97 |
13 | 90c83134a7a |
14 | 4479bd6badd |
15 | 2281eeac141 |
hex | 12347536753 |
1251032131411 has 2 divisors, whose sum is σ = 1251032131412. Its totient is φ = 1251032131410.
The previous prime is 1251032131403. The next prime is 1251032131471. The reversal of 1251032131411 is 1141312301521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1251032131411 - 23 = 1251032131403 is a prime.
It is not a weakly prime, because it can be changed into another prime (1251032131471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625516065705 + 625516065706.
It is an arithmetic number, because the mean of its divisors is an integer number (625516065706).
Almost surely, 21251032131411 is an apocalyptic number.
1251032131411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1251032131411 is an equidigital number, since it uses as much as digits as its factorization.
1251032131411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 1251032131411 its reverse (1141312301521), we get a palindrome (2392344432932).
The spelling of 1251032131411 in words is "one trillion, two hundred fifty-one billion, thirty-two million, one hundred thirty-one thousand, four hundred eleven".
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