Base | Representation |
---|---|
bin | 10010001101001011100… |
… | …111000000100000001011 |
3 | 11102121022120220021220121 |
4 | 102031023213000200023 |
5 | 130444230111000021 |
6 | 2354425500404111 |
7 | 156250344351505 |
oct | 22151347004013 |
9 | 4377276807817 |
10 | 1251104000011 |
11 | 442654656748 |
12 | 182580246637 |
13 | 90c94ca8c78 |
14 | 447a7718d75 |
15 | 22826456741 |
hex | 1234b9c080b |
1251104000011 has 2 divisors, whose sum is σ = 1251104000012. Its totient is φ = 1251104000010.
The previous prime is 1251103999969. The next prime is 1251104000057. The reversal of 1251104000011 is 1100004011521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1251104000011 - 219 = 1251103475723 is a prime.
It is a super-2 number, since 2×12511040000112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1251104000071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625552000005 + 625552000006.
It is an arithmetic number, because the mean of its divisors is an integer number (625552000006).
Almost surely, 21251104000011 is an apocalyptic number.
1251104000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1251104000011 is an equidigital number, since it uses as much as digits as its factorization.
1251104000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 1251104000011 its reverse (1100004011521), we get a palindrome (2351108011532).
The spelling of 1251104000011 in words is "one trillion, two hundred fifty-one billion, one hundred four million, eleven", and thus it is an aban number.
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