Base | Representation |
---|---|
bin | 111010010000101110… |
… | …0011011111010000011 |
3 | 102221221111020100201111 |
4 | 1310201130123322003 |
5 | 4022213434412201 |
6 | 133251015544151 |
7 | 12016320155656 |
oct | 1644134337203 |
9 | 387844210644 |
10 | 125115154051 |
11 | 49074274068 |
12 | 202b898b057 |
13 | ba4bb64244 |
14 | 60ac82189d |
15 | 33c40a6b51 |
hex | 1d2171be83 |
125115154051 has 4 divisors (see below), whose sum is σ = 125202465432. Its totient is φ = 125027842672.
The previous prime is 125115154049. The next prime is 125115154057. The reversal of 125115154051 is 150451511521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125115154051 - 21 = 125115154049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125115154057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43653541 + ... + 43656406.
It is an arithmetic number, because the mean of its divisors is an integer number (31300616358).
Almost surely, 2125115154051 is an apocalyptic number.
125115154051 is a deficient number, since it is larger than the sum of its proper divisors (87311381).
125115154051 is an equidigital number, since it uses as much as digits as its factorization.
125115154051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87311380.
The product of its (nonzero) digits is 5000, while the sum is 31.
Adding to 125115154051 its reverse (150451511521), we get a palindrome (275566665572).
The spelling of 125115154051 in words is "one hundred twenty-five billion, one hundred fifteen million, one hundred fifty-four thousand, fifty-one".
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