Base | Representation |
---|---|
bin | 111010010000111101… |
… | …0111010011100011011 |
3 | 102221222001021021010012 |
4 | 1310201322322130123 |
5 | 4022223011042301 |
6 | 133251503112135 |
7 | 12016445112455 |
oct | 1644172723433 |
9 | 387861237105 |
10 | 125123143451 |
11 | 49078830679 |
12 | 202bb5a264b |
13 | ba507008b7 |
14 | 60ad9012d5 |
15 | 33c4b33ebb |
hex | 1d21eba71b |
125123143451 has 2 divisors, whose sum is σ = 125123143452. Its totient is φ = 125123143450.
The previous prime is 125123143339. The next prime is 125123143471. The reversal of 125123143451 is 154341321521.
It is a strong prime.
It is an emirp because it is prime and its reverse (154341321521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125123143451 - 230 = 124049401627 is a prime.
It is not a weakly prime, because it can be changed into another prime (125123143471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62561571725 + 62561571726.
It is an arithmetic number, because the mean of its divisors is an integer number (62561571726).
Almost surely, 2125123143451 is an apocalyptic number.
125123143451 is a deficient number, since it is larger than the sum of its proper divisors (1).
125123143451 is an equidigital number, since it uses as much as digits as its factorization.
125123143451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 32.
Adding to 125123143451 its reverse (154341321521), we get a palindrome (279464464972).
The spelling of 125123143451 in words is "one hundred twenty-five billion, one hundred twenty-three million, one hundred forty-three thousand, four hundred fifty-one".
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