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125131250007 = 341544830247
BaseRepresentation
bin111010010001001100…
…1110101100101010111
3102221222121112010020000
41310202121311211113
54022232100000012
6133252352542343
712016604034651
oct1644231654527
9387877463200
10125131250007
1149082368205
12203022519b3
13ba522ab68a
1460b0a116d1
1533c56d5ddc
hex1d22675957

125131250007 has 10 divisors (see below), whose sum is σ = 186924460008. Its totient is φ = 83420833284.

The previous prime is 125131249973. The next prime is 125131250009. The reversal of 125131250007 is 700052131521.

125131250007 is a `hidden beast` number, since 1 + 25 + 131 + 2 + 500 + 0 + 7 = 666.

It is not a de Polignac number, because 125131250007 - 27 = 125131249879 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125131250009) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 772415043 + ... + 772415204.

Almost surely, 2125131250007 is an apocalyptic number.

125131250007 is a deficient number, since it is larger than the sum of its proper divisors (61793210001).

125131250007 is an equidigital number, since it uses as much as digits as its factorization.

125131250007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1544830259 (or 1544830250 counting only the distinct ones).

The product of its (nonzero) digits is 2100, while the sum is 27.

Adding to 125131250007 its reverse (700052131521), we get a palindrome (825183381528).

The spelling of 125131250007 in words is "one hundred twenty-five billion, one hundred thirty-one million, two hundred fifty thousand, seven".

Divisors: 1 3 9 27 81 1544830247 4634490741 13903472223 41710416669 125131250007