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125132544033521 is a prime number
BaseRepresentation
bin11100011100111010110000…
…110101100100001011110001
3121102001112222010212200220012
4130130322300311210023301
5112400132422233033041
61122045032552024305
735233346043510113
oct3434726065441361
9542045863780805
10125132544033521
11369644609a9942
121204b637992095
1354a8c4347162b
1422c8639b153b3
15e6eeb82133eb
hex71ceb0d642f1

125132544033521 has 2 divisors, whose sum is σ = 125132544033522. Its totient is φ = 125132544033520.

The previous prime is 125132544033509. The next prime is 125132544033547. The reversal of 125132544033521 is 125330445231521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77040205335025 + 48092338698496 = 8777255^2 + 6934864^2 .

It is an emirp because it is prime and its reverse (125330445231521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125132544033521 - 242 = 120734497522417 is a prime.

It is not a weakly prime, because it can be changed into another prime (125132544053521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62566272016760 + 62566272016761.

It is an arithmetic number, because the mean of its divisors is an integer number (62566272016761).

Almost surely, 2125132544033521 is an apocalyptic number.

It is an amenable number.

125132544033521 is a deficient number, since it is larger than the sum of its proper divisors (1).

125132544033521 is an equidigital number, since it uses as much as digits as its factorization.

125132544033521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 125132544033521 in words is "one hundred twenty-five trillion, one hundred thirty-two billion, five hundred forty-four million, thirty-three thousand, five hundred twenty-one".