Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1001000000110101000011 |
3 | 1122022020220212101011010021 |
4 | 2312011320221000311003 |
5 | 3120004131010003332 |
6 | 42340303005314311 |
7 | 2431024224631324 |
oct | 266057051006503 |
9 | 48266825334107 |
10 | 12513263750467 |
11 | 3a94933192347 |
12 | 14a11a2865997 |
13 | 6c9cc37576cc |
14 | 3139065c644b |
15 | 16a773203c97 |
hex | b6178a40d43 |
12513263750467 has 2 divisors, whose sum is σ = 12513263750468. Its totient is φ = 12513263750466.
The previous prime is 12513263750419. The next prime is 12513263750489. The reversal of 12513263750467 is 76405736231521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12513263750467 - 231 = 12511116266819 is a prime.
It is not a weakly prime, because it can be changed into another prime (12513263750567) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256631875233 + 6256631875234.
It is an arithmetic number, because the mean of its divisors is an integer number (6256631875234).
Almost surely, 212513263750467 is an apocalyptic number.
12513263750467 is a deficient number, since it is larger than the sum of its proper divisors (1).
12513263750467 is an equidigital number, since it uses as much as digits as its factorization.
12513263750467 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6350400, while the sum is 52.
Adding to 12513263750467 its reverse (76405736231521), we get a palindrome (88918999981988).
The spelling of 12513263750467 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty thousand, four hundred sixty-seven".
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