Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1001000010010000010011 |
3 | 1122022020220212101110010120 |
4 | 2312011320221002100103 |
5 | 3120004131010200212 |
6 | 42340303005401323 |
7 | 2431024224654336 |
oct | 266057051022023 |
9 | 48266825343116 |
10 | 12513263756307 |
11 | 3a94933196776 |
12 | 14a11a2869243 |
13 | 6c9cc375a272 |
14 | 3139065c861d |
15 | 16a77320588c |
hex | b6178a42413 |
12513263756307 has 8 divisors (see below), whose sum is σ = 16685060264400. Its totient is φ = 8341821542880.
The previous prime is 12513263756293. The next prime is 12513263756341. The reversal of 12513263756307 is 70365736231521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12513263756307 - 24 = 12513263756291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12513263756307.
It is not an unprimeable number, because it can be changed into a prime (12513263716307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 88491244 + ... + 88632537.
It is an arithmetic number, because the mean of its divisors is an integer number (2085632533050).
Almost surely, 212513263756307 is an apocalyptic number.
12513263756307 is a deficient number, since it is larger than the sum of its proper divisors (4171796508093).
12513263756307 is a wasteful number, since it uses less digits than its factorization.
12513263756307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177147333.
The product of its (nonzero) digits is 4762800, while the sum is 51.
Adding to 12513263756307 its reverse (70365736231521), we get a palindrome (82878999987828).
The spelling of 12513263756307 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, three hundred seven".
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