1251421034131 has 4 divisors (see below), whose sum is σ = 1266498396072. Its totient is φ = 1236343672192.

The previous prime is 1251421034099. The next prime is 1251421034141. The reversal of 1251421034131 is 1314301241521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1251421034131 - 2⁵ = 1251421034099 is a prime.

It is a super-2 number, since 2×1251421034131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1251421034131.

It is not an unprimeable number, because it can be changed into a prime (1251421034141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7538680846 + ... + 7538681011.

It is an arithmetic number, because the mean of its divisors is an integer number (316624599018).

Almost surely, 2^{1251421034131} is an apocalyptic number.

1251421034131 is a deficient number, since it is larger than the sum of its proper divisors (15077361941).

1251421034131 is an equidigital number, since it uses as much as digits as its factorization.

1251421034131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15077361940.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 1251421034131 its reverse (1314301241521), we get a palindrome (2565722275652).

The spelling of 1251421034131 in words is "one trillion, two hundred fifty-one billion, four hundred twenty-one million, thirty-four thousand, one hundred thirty-one".