Base | Representation |
---|---|
bin | 10010001101011110110… |
… | …000101100001011101001 |
3 | 11102122010222111021221021 |
4 | 102031132300230023221 |
5 | 131000404334232241 |
6 | 2354521415212441 |
7 | 156261325404622 |
oct | 22153660541351 |
9 | 4378128437837 |
10 | 1251425305321 |
11 | 4427a9a62124 |
12 | 18264b977121 |
13 | 91016726359 |
14 | 447d8276a49 |
15 | 228447730d1 |
hex | 1235ec2c2e9 |
1251425305321 has 2 divisors, whose sum is σ = 1251425305322. Its totient is φ = 1251425305320.
The previous prime is 1251425305213. The next prime is 1251425305337. The reversal of 1251425305321 is 1235035241521.
Together with previous prime (1251425305213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1124318794921 + 127106510400 = 1060339^2 + 356520^2 .
It is an emirp because it is prime and its reverse (1235035241521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1251425305321 - 211 = 1251425303273 is a prime.
It is not a weakly prime, because it can be changed into another prime (1251425315321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625712652660 + 625712652661.
It is an arithmetic number, because the mean of its divisors is an integer number (625712652661).
Almost surely, 21251425305321 is an apocalyptic number.
It is an amenable number.
1251425305321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1251425305321 is an equidigital number, since it uses as much as digits as its factorization.
1251425305321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 1251425305321 in words is "one trillion, two hundred fifty-one billion, four hundred twenty-five million, three hundred five thousand, three hundred twenty-one".
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